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A and B together can complete a work in3 days. They start together but after 2 days, Bleft the work. If the work is completed aftertwo more days, B alone could do the work in |
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Answer» Answer: 1st Method: (A+B)'s one DAY's work = 1/3 PART; (A+B) WORKS 2 days together = 2/3 part; Remaining work = 1-(2/3) = 1/3 part; 1/3 part of work is completed by A in two days; Hence, one day's work of A = 1/6; Then, one day's work of B = 1/3-1/6=1/6; So, B alone can COMPLETE the whole work in 6 days. 2nd method: (A+B)'s one day's % work = 100/3 = 33.3% Work completed in 2 days = 66.6% Remaining work = 33.4%; One day's % work of A = 33.4/2 = 16.7%; One day's work of B = 33.3 - 16.7 = 16.7%; B alone can complete the work in, = 100/16.7 = 6 days. |
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