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InterviewSolution
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A and Bare two radioctivesubstancewith half lives 20 min and d30 min respectively. Startingfrom equal numberof moles A and B , after1hr , whatis the (a) ratio ofmoles of A and B and (b) ratio of activityof A and B ? |
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Answer» Solution :The GIVEN TIME, 1 hour is 3 `t_(1//2)` for substance A and 2 `t_(1//2)` for substance B The fraction of A left after 3 `t_(1//2)=1//2^(3)=1//8` The fraction of B left after 2 `t_(1//2)=1//2^(2)=1//4` (a) The ratio of moles left `-1//8,1//4-1:2`. (b) The ratio of activities `=(lamda_(A)N_(A))/(lamda_(B)N_(B))=(N_(A)(t_(1//2))_(B))/(N_(B)(t_(1//2))_(A))=((1//8)xx30)/((1//4)xx20)=3:4` |
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