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(a) Answer the following question: (i) Which element of the first transition series has highest second ionisation enthalpy? (ii) Which element of the first transition series has highest third ionisation enthalpy? (iii) Which elements of the first transition series has lowest enthalpy of atomisation? (b) Identify the metal and justify your answer: (i) Carbonyl M(CO)_(5) (ii) MO_(3)F |
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Answer» Solution :(a) (i) Cu In Cu the second ELECTRON is to be removed from `3d^(10)` CONFIGURATION which is highly stable. (ii) Zn The third electron is to be removed from `d^(10)` configuration which is highly stable. (iii) Zn-Zinc has all electrons paired and HENCE it cannot form metallic bonds. (b) (i) `Fe(CO)_(5)` As per Effective Atomic NUMBER (EAN) rule EAN=Z- [Number of electrons lost to form metalion] + [Number of electrons gained from donor atom] `:.` EAN `=26-0 + (5 xx 2)= 36` (ii) `MnO_(3)F`: Mn shown (+7) oxidation state. |
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