1.

A aqueous solution containing 1.248 g of barium chloride (molar mass ="208.34 g mol"^(-1)) in 100 g of water boids at 100.0832^(@)C. Calculate the degree of dissociation of BaCl_(2)(K_(b)" for water= 0.52 K kg mol"^(-1)).

Answer»


SOLUTION :`M_(2)"(OBSERVED)"=(1000xx0.52xx1.248)/(100xx0.0832)="78 g mol"^(-1)""THEREFORE""i=(208.34)/(78)=2.67`
`""{:(BaCl_(2), rarr,BA^(2+),+,2Cl^(-),),("1 mol",,,,,),(1-alpha,,alpha,,2alpha,"Total"=1+2alpha):}`
`i=1+2 alpha "or"alpha=(i-1)/(2)=(1.67)/(2)=0.835.`


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