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(a) At what distance should the lens be held from the figure in Exercise 9.23 in order to view the squares distinctly with the maximum possible magnifying power ? (b) What is the magnification in this case ? (c) Is the magnification equal to the magnifying power in this case ? Explain |
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Answer» Solution :(a) For maximum magnifying power `v=-D =-25 cm` and `F= + 9 cm` Hence, `1/u =1/v -1/f -1/(-25) -1/9 rArr MU = -6.6 cm` (b) Magnification `m =(-25)/(-6.6) = 3.8` (c) YES, in this CASE the magnification is equal to the magnifying power because now the image is being formed at NEAR point of eye. |
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