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(a+b)2=A2+b2+2ab please answer. This is a maths question. Do it in distributive law |
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Answer» -STEP explanation:(a+b)²= (a+b)×(a+b)= (a+b)(a+b)= [a×(a+b)]+[b×(a+b)]= [a(a+b)]+[b(a+b)]= [{(a×a)+(a×b)}] + [{(b×a)+(b×b)}]= [(a²)+(ab)] + [(ba)+(b²)]= (a²)+(ab)+(ba)+(b²)Since a×b = b×a (commutative property), ba = ab.= (a²)+(ab)+(ab)+(b²)= (a²)+(2×ab)+(b²)= (a²)+(2ab)+(b²)Without Algebra, proof that (a+b)² is not equal to a²+b²Let a = 5, and b = 4.In (a+b)²,= (5+4)²= (9)²= 9×9= 81,Whereas in a² + b²= 5² + 4²= 25 + 16= 41.Order of operations makes all the difference, if you add 5 and 4 before squaring the term, the answer is 81, whereas if you square 5 and then square 4 and add the TWO results, the FINAL answer is different. And the Parentheses are placed in (a+b)² is just so as to signify that the two terms, “a” and “b” are to be added before squaring them. (a+b)² will always be greater than a² + b².MARK ME AS BRAINLIST ANSWER |
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