1.

A, B and C are three complexes of chromium (III) with the empirical formula H_(12)O_(6)Cl_(3)Cr. All the three complexes have water and chlorie ions as ligands. Complex A does not react with conc. H_(2)SO_(4) whereas complexes B and C lose 6.75% and 13.5% of their original weight respectively, on treatment with concentrated H_(2)SO_(4). The complex C is

Answer»

`[Cr(H_(2)O)_(4)Cl_(2)].2H_(2)O`
`[Cr(H_(2)O)_(5)CL]Cl_(2).H_(2)O`
`[Cr(H_(2)O)_(3)Cl_(3)].3H_(2)O`
`[Cr(H_(2)O)_(6)]Cl_(3)`

Solution :`C=[Cr(H_(2)O)_(4)Cl_(2)]Cl.2 H_(2)O overset(H_(2)SO_(4))rarr` 2 moles of `H_(2)O` is REMOVED
`% " loss "= (2xx18)/(266.5)xx10=13.50%`


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