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A+b+c =9 ab+bc+ac=15 find the value of a²+b²+c² |
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Answer» Since (a + B + c)2 = a2 + b2 + c2 + 2 (AB + BC + ca) ∴ (9)2 = a2 + b2 + c2 + 2(15) 81 = a2 + b2 + c2 + 30 ∴ a2 + b2 + c2 = 81 – 30 = 51 |
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