1.

A+b+c =9 ab+bc+ac=15 find the value of a²+b²+c²​

Answer»

Since (a + B + c)2 = a2 + b2 + c2 + 2 (AB + BC + ca)

∴ (9)2 = a2 + b2 + c2 + 2(15)

81 = a2 + b2 + c2 + 30

∴ a2 + b2 + c2 = 81 – 30 = 51



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