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A, B, C and D have position vectors `veca, vecb, vecc and vecd`, repectively, such that `veca-vecb = 2(vecd-vecc)`. ThenA. AB and CD bisect each otherB. BD and AC bisect each otherC. AB and CD trisect each otherD. BD and AC trisect each other |
Answer» Correct Answer - D `veca-vecb= 2(vecd-vecc)` `therefore (veca+ 2vecc)/(2+1) = (vecb+ 2vecd)/(2+1)` ltBrgt Hence, AC and BD trisect each other as L.H.S is the position vector of a point trisecting A an C, and R.H.S that of B and D. |
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