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`a`, `b`, `c` are positive integers formaing an incresing `G.P.` and `b-a` is a perfect cube and `log_(6)a+log_(6)b+log_(6)c=6`, then `a+b+c=`A. `100`B. `111`C. `122`D. `189` |
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Answer» Correct Answer - D `(d)` `log_(6)(abc)=6` `implies(abc)=6^(6)` Let `a=(b)/(r )` and `c=br` ,brgt `impliesb=36` and `a=(36)/(r )impliesr=2,3,4,6,9,12,18` Also `36(1-(1)/(r ))` is a perfect cube. `impliesr=4` `impliesa+b+c=9+36+144=189` |
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