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`(a.(b xx c))/(b.(c xx a))+(b.(a x b))/(a. (b xx c))` is equal toA. 1B. 2C. 0D. `oo` |
Answer» Correct Answer - B Now, `(a*(bxxc))/(b*(cxxa))+(b*(axxb))/(a*(axxc))=([abc])/(["bca"])+([bab])/(["abc"])` `=1+0=1" "[because[bab]=0]` |
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