A bag contain 5 red and 2 green balls. At random a ball is drawn from this pot. If a drawn ball is green then put a red ball in the pot and if a drawn ball is red, then put a green ball in the pot, while drawn ball is not replace in the pot. Now we draw another ball randomnly, the probability of second ball to be red isA. `(27)/(49)`B. `(26)/(49)`C. `(21)/(49)`D. `(32)/(49)`

A bag contain 5 red and 2 green balls. At random a ball is drawn from

1.	A bag contain 5 red and 2 green balls. At random a ball is drawn from this pot. If a drawn ball is green then put a red ball in the pot and if a drawn ball is red, then put a green ball in the pot, while drawn ball is not replace in the pot. Now we draw another ball randomnly, the probability of second ball to be red isA. `(27)/(49)`B. `(26)/(49)`C. `(21)/(49)`D. `(32)/(49)`
Answer» Correct Answer - D Let A be the event that ball drawn is given and B be the event that ball drawn is red. `:." "P(A)=(2)/(7)" and "P(B)=(5)/(7)` Again, let C be the event that second ball drawn is red. `:." "P(C)=P(A)P(C//A)+P(B)P(C//B)` `=(2)/(7)xx(6)/(7)+(5)/(7)xx(4)/(7)` `=(12+40)/(49)=(32)/(49)`

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