A bag contains 10 balls each marked with one of the digits 0 to 9. If

1.	A bag contains 10 balls each marked with one of the digits 0 to 9. If four balls are drawn successively with replacement from the bag, what is the probability that none is marked with the digit 0 ?
Answer» A bag contains 10 balls each marked with one of the digit from 0 to 9. Probability that one ball is in marked 0 drawn P = 1/10 = 0.1 = 0.1 Probability that ball is not marked 0 q = 1 – p = 1 – 0.1 = 0.9 Now 4 balls are drawn successively with replacement. ∴ Probability that any of them ball is marked 0 = P(X = 0) = 4C₀p⁰q⁴ = (0.9)⁴ = (9/10)⁴

A bag contains 10 balls each marked with one of the digits 0 to 9. If four balls are drawn successively with replacement from the bag, what is the probability that none is marked with the digit 0 ?

Answer»

A bag contains 10 balls each marked with one of the digit from 0 to 9.

Probability that one ball is in marked 0 drawn

P = 1/10 = 0.1 = 0.1

Probability that ball is not marked 0

q = 1 – p

= 1 – 0.1 = 0.9

Now 4 balls are drawn successively with replacement.

∴ Probability that any of them ball is marked 0

= P(X = 0) = 4C₀p⁰q⁴

= (0.9)⁴ = (9/10)⁴

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A bag contains 10 balls each marked with one of the digits 0 to 9. If four balls are drawn successively with replacement from the bag, what is the probability that none is marked with the digit 0 ?

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