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A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white and the first ball drawn is green? The balls are replaced in the bag.(a) \(\frac {1}{9}\)(b) \(\frac {2}{9}\)(c) \(\frac {8}{81}\)(d) \(\frac {2}{81}\)I had been asked this question in an online quiz.My question is based upon Probability topic in division Probability of Mathematics – Class 12 |
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Answer» Right choice is (c) \(\frac {8}{81}\) |
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