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A bag contains 3 red balls, 5 black balls and 4 white balls. A balls is drawn at random from the bag. What is the probability that the ball drawn is: (i) white? (ii) red? (iii) black? (iv) not red? |
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Answer» Total number of possible outcomes, n(S) = 12 {3 red balls, 5 black balls and 4 white balls) (i) n(E) = 4 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{4}{12}\) = \(\frac{1}{3}\) (ii) n(E) = 3 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{3}{12}\) = \(\frac{1}{4}\) (iii) n(E) = 5 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{5}{12}\) (iv) n(E) = 9 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{9}{12}\) = \(\frac{3}{4}\) |
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