1.

A bag contains 3 red balls, 5 black balls and 4 white balls. A balls is drawn at random from the bag. What is the probability that the ball drawn is: (i) white? (ii) red? (iii) black? (iv) not red?

Answer»

Total number of possible outcomes, n(S) = 12 {3 red balls, 5 black balls and 4 white balls) 

(i) n(E) = 4

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{4}{12}\) = \(\frac{1}{3}\)

(ii) n(E) = 3

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{3}{12}\) = \(\frac{1}{4}\)

(iii) n(E) = 5

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{5}{12}\)

(iv) n(E) = 9

 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{9}{12}\) = \(\frac{3}{4}\)



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