A bag contains 3 red balls and 5 black balls. A ball is drawn at rando

1.	A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red? (ii) not red ?
Answer» A bag contains 3 red balls, 5 black balls. Totally there are 8 balls. ∴ n(S) = 8 i) Possibility that the red ball drawn, n(E) = 3 ∴ Probability, P(E) = \(\frac{n(E)}{n(S)} = \frac{3}{8}\) (ii) Possibility that the 1 black ball drwn is n(F) = 5 ∴ Probability, P(F) = \(\frac{n(F)}{n(S)} = \frac{5}{8}\)

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red? (ii) not red ?

Answer»

A bag contains 3 red balls, 5 black balls.

Totally there are 8 balls.

∴ n(S) = 8

i) Possibility that the red ball drawn, n(E) = 3

∴ Probability, P(E) = \(\frac{n(E)}{n(S)} = \frac{3}{8}\)

(ii) Possibility that the 1 black ball drwn is n(F) = 5

∴ Probability, P(F) = \(\frac{n(F)}{n(S)} = \frac{5}{8}\)

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A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red? (ii) not red ?

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