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A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is(i) red?(ii) not red? |
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Answer» Total no. of possible outcomes = 8 {3 red, 5 black} (i) E ⟶ event of getting red ball. No. of favourable outcomes = 3 {3 red} Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) P(E) = 3/8 (ii) Bar E ⟶ event of getting no red ball. ()+P(Bar E)=1 P(̅)=1−P(Bar E) = 1 − 3/8 = 5/8 |
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