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A bag contains 3 White, 3 black and 2 red balls. One by one three balls are drawn without replacement. Find the probability that third ballis red |
Answer» P(0R)=`6C_2/(8C_2)*2/6=5/28` P(1R)=`(2C_16c_1)/(8C_2)*1/6=1/14` P=`5/28+1/14=1/4`. |
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