A bag contains 4 blue, 5 red and 7 green balls. If 4 balls are drawn o

1.	A bag contains 4 blue, 5 red and 7 green balls. If 4 balls are drawn one by one with replacement, what is the probability that all are blue?(a) \(\frac{1}{16}\)(b) \(\frac{1}{4}\)(c) \(\frac{1}{256}\)(d) \(\frac{1}{64}\)
Answer» (c) \(\frac{1}{256}\) Probability of drawing a blue ball = \(\frac{4}{4+5+7}\) = \(\frac{4}{16}\)= \(\frac{1}{4}\) \(\therefore\) Required probability = \(\frac{1}{4}\) x \(\frac{1}{4}\) x \(\frac{1}{4}\) x \(\frac{1}{4}\) = \(\frac{1}{256}\).

A bag contains 4 blue, 5 red and 7 green balls. If 4 balls are drawn one by one with replacement, what is the probability that all are blue?(a) \(\frac{1}{16}\)(b) \(\frac{1}{4}\)(c) \(\frac{1}{256}\)(d) \(\frac{1}{64}\)

Answer»

(c) \(\frac{1}{256}\)

Probability of drawing a blue ball

= \(\frac{4}{4+5+7}\) = \(\frac{4}{16}\)= \(\frac{1}{4}\)

\(\therefore\) Required probability = \(\frac{1}{4}\) x \(\frac{1}{4}\) x \(\frac{1}{4}\) x \(\frac{1}{4}\) = \(\frac{1}{256}\).

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A bag contains 4 blue, 5 red and 7 green balls. If 4 balls are drawn one by one with replacement, what is the probability that all are blue?(a) \(\frac{1}{16}\)(b) \(\frac{1}{4}\)(c) \(\frac{1}{256}\)(d) \(\frac{1}{64}\)

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