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A bag contains 4 red and 7 blue balls. What is the probability of drawing a blue ball if the first ball drawn is red? The balls drawn are not replaced in the bag.(a) \(\frac {7}{10}\)(b) \(\frac {8}{10}\)(c) \(\frac {7}{1}\)(d) \(\frac {4}{11}\)I have been asked this question during an online exam.This interesting question is from Multiplication Theorem on Probability topic in division Probability of Mathematics – Class 12

Answer»

The correct option is (a) \(\frac {7}{10}\)

To explain I would SAY: Total number of balls = 4 + 7 = 11

The probability of the first ball to be red = \(\frac {4}{11}\)

The probability of drawing BLUE ball as the second ball out without replacement = \(\frac {7}{10}\)



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