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A bag contains 4 red and 7 blue balls. What is the probability of drawing a red ball if the first ball drawn is blue? The balls drawn are not replaced in the bag.(a) \(\frac {7}{11}\)(b) \(\frac {7}{10}\)(c) \(\frac {4}{10}\)(d) \(\frac {9}{11}\)I got this question in a job interview.I need to ask this question from Multiplication Theorem on Probability in chapter Probability of Mathematics – Class 12

Answer»

Correct CHOICE is (c) \(\frac {4}{10}\)

Easy explanation: Total number of balls = 4 + 7 = 11

The PROBABILITY of the FIRST ball to be BLUE = \(\frac {7}{11}\)

The probability of drawing red ball as the second ball out without replacement = \(\frac {4}{10}\)



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