A bag contains 4 white and 5 black balls. A ball is drawn at random fr

1.	A bag contains 4 white and 5 black balls. A ball is drawn at random from the bag. Find the probability that the ball is drawn is white.
Answer» We know that, Probability of occurrence of an event = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) By permutation and combination, total no. of ways to pick r objects from given n objects is ⁿC_r Now, total no. of ways to pick a ball from 9 balls is ⁹c₁ = 9 Our desired output is to pick a white ball. So, no. of ways to pick a white ball from 4 white balls (because the white ball can be picked from only white balls) is ⁴c₁ = 4 Therefore, the probability of picking a white ball = \(\frac{4}{9}\) Conclusion: Probability of picking a white ball from 4 white balls and 5 white balls is \(\frac{4}{9}\)

A bag contains 4 white and 5 black balls. A ball is drawn at random from the bag. Find the probability that the ball is drawn is white.

Answer»

We know that,

Probability of occurrence of an event

= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)

By permutation and combination, total no. of ways to pick r objects from given n objects is ⁿC_r

Now, total no. of ways to pick a ball from 9 balls is ⁹c₁ = 9

Our desired output is to pick a white ball. So, no. of ways to pick a white ball from 4 white balls (because the white ball can be picked from only white balls) is ⁴c₁ = 4

Therefore, the probability of picking a white ball = \(\frac{4}{9}\)

Conclusion: Probability of picking a white ball from 4 white balls and 5 white balls is \(\frac{4}{9}\)

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