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.A bag contains 5 green marbles, 3 blue marbles, 2 red marbles and 2 yellow marbles. One marble is drawn out randomly. Find the probability of p(green) , p(blue), p(red) and p(yellow) |
| Answer» TOTAL no. of POSSIBLE OUTCOMES = 5+3+2+2 = 12.P (green) = 5/12.P (blue) = 3/12 = 1/4.P (red) = 2/12 = 1/6.P (YELLOW) = 2/12 = 1)6.Hope this helps!!!! | |