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A bag contains 5 red,8 green and 7 white balls. One ball is drawn at random from the bag, find the probability of getting :(i) not a white ball,(ii) neither a green nor a red ball. |
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Answer» Total balls = 5 + 8 + 7 = 20 (i) P(white ball) = 7/20 P(not white) = 1 - 7/20 = 13/20 (ii) P(green or red) = (8 + 5)/20 = 13/20 P(neither green nor red) = 1 - (13/20) = 7/20 |
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