1.

A bag contains 6 blue and 5 yellow balls. 4 balls are drawn successively without replacement. What is the probability that the balls are alternately of different colours?1). 7/332). 5/333). 3/114). 1/9

Answer»

FINAL ANSWER = (Starting with a blue ball) OR (Starting with a YELLOW ball)

Final Answer = (6C1/11C1 × 5C1/10C1 × 5C1/9C1 × 4C1/8C1) + (5C1/11C1 × 6C1/10C1 × 4C1/9C1 × 5C1/8C1)

∴ Final answer = (6/11 × 5/10 × 5/9× 4/8) + (5/11 × 6/10 × 4/9 × 5/8)

∴ The REQUIRED probability is 5/33



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