A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at ra

1.	A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is(i) Red or white(ii) Not black(iii) Neither white nor black
Answer» Total no. of possible outcomes = 8 + 6 + 4 = 18 {8 red, 6 white, 4 black} (i) E ⟶ event of getting red or white ball No. of favourable outcomes = 4 {4 black balls} P(E) = 4/18 = 2/9 (Bar E) ⟶event of not getting black ball P(Bar E)=1−P(E)=1−2/9 = 7/9 (ii) E ⟶ event of getting neither white nor black. No. of favourable outcomes = 15 – 6 – 4 = 8 {Total balls – no. of white balls – no. of black balls} P(E) = 8/18 = 4/9

A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is(i) Red or white(ii) Not black(iii) Neither white nor black

Answer»

Total no. of possible outcomes = 8 + 6 + 4 = 18 {8 red, 6 white, 4 black}

(i) E ⟶ event of getting red or white ball

No. of favourable outcomes = 4 {4 black balls}

P(E) = 4/18 = 2/9

(Bar E) ⟶event of not getting black ball

P(Bar E)=1−P(E)=1−2/9 = 7/9

(ii) E ⟶ event of getting neither white nor black.

No. of favourable outcomes = 15 – 6 – 4 = 8 {Total balls – no. of white balls – no. of black balls}

P(E) = 8/18 = 4/9

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A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is(i) Red or white(ii) Not black(iii) Neither white nor black

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