A bag contains cards numbered from 1 to 25. A card is drawn at random

1.	A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 isA. \(\frac{1}5\)B. \(\frac{3}{25}\)C. \(\frac{4}{25}\)D.\(\frac{2}{25}\)
Answer» Total numbers of elementary events are: 25 Let E be the event of getting number divisible by both 2 and 3 Favorable outcomes are: { 6, 12, 18, 24} Numbers of favorable outcomes are: 4 P (number divisible by 2 and 3) = P (E) = \(\frac{4}{25}\)

A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 isA. \(\frac{1}5\)B. \(\frac{3}{25}\)C. \(\frac{4}{25}\)D.\(\frac{2}{25}\)

Answer»

Total numbers of elementary events are: 25

Let E be the event of getting number divisible by both 2 and 3

Favorable outcomes are: { 6, 12, 18, 24}

Numbers of favorable outcomes are: 4

P (number divisible by 2 and 3) = P (E) = \(\frac{4}{25}\)

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A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 isA. \(\frac{1}5\)B. \(\frac{3}{25}\)C. \(\frac{4}{25}\)D.\(\frac{2}{25}\)

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