A bag of mass `M` hangs by a long massless rope. A bullet of mass in, moving horizontally with velocity `u`, is caught in the bag. Then for the combined (bag `+` bullet) system, just after collisionA. Momentum is `(mvM)/(M+m)`B. kinetic energy is `(mv^(2))/(2)`C. Momentum is `(mv(M+m))/(M)`D. kinetic energy is `(m^(2)v^(2))/(2(M+m))`

A bag of mass `M` hangs by a long massless rope. A bullet of mass in,

1.	A bag of mass `M` hangs by a long massless rope. A bullet of mass in, moving horizontally with velocity `u`, is caught in the bag. Then for the combined (bag `+` bullet) system, just after collisionA. Momentum is `(mvM)/(M+m)`B. kinetic energy is `(mv^(2))/(2)`C. Momentum is `(mv(M+m))/(M)`D. kinetic energy is `(m^(2)v^(2))/(2(M+m))`
Answer» Correct Answer - D

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