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A ball A of mass m moving along positive x-direction with kinetic energy K and momentum p undergoes elastic head on collision with a stationary ball B of mass M after collision the ball A moves along negative x-direction with kinetic energy K//9, final momentum of B is |
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Answer» p `12MV_(1)^(2)=K/9` ` implies V_(1)= sqrt((2K)/(9M))` `K=1/2MV^(2)=1/2(MV^(2))/M=p^(2)/(2M)` `Mu_(1)=-MV_(1)+p_(B)` `M(u_(1)+V_(1))=p_(B)` `P_(B)=M[sqrt((2K)/M)+ sqrt((2K)/9K)]` `=sqrt(2MK) + sqrt(2MK)/K` `=p+p/3` `(4p)/3` |
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