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A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2, calculate its speed on reaching the ground and the height of the table. |
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Answer» Data: t = 1s, g = 10 m/s2, u = 0 m/s, s = ?, v = ? (i) s = ut + \(\frac{1}{2}\)gt2 = \(\frac{1}{2}\)gt2 for u = 0 m/s ∴ s = \(\frac{1}{2}\) × 10 m/s2 × (1s)2 = 5 m ∴ The height of the table = 5 m. (ii) v = u + at = u + gt = 0 m/s + 10 m/s2 × 1 s = 10m/s ∴ The velocity of the ball on reaching the ground = 10 m/s. |
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