1.

A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2, calculate its speed on reaching the ground and the height of the table.

Answer»

Data: t = 1s, g = 10 m/s2, u = 0 m/s,

s = ?, v = ?

(i) s = ut + \(\frac{1}{2}\)gt2

\(\frac{1}{2}\)gt2 for u = 0 m/s

∴ s = \(\frac{1}{2}\) × 10 m/s2 × (1s)2

= 5 m

∴ The height of the table = 5 m.

(ii) v = u + at = u + gt

= 0 m/s + 10 m/s2 × 1 s

= 10m/s

∴ The velocity of the ball on reaching the ground = 10 m/s.



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