A ball falls on the surface from 10 m height and rebounds to 2.5 m. If the duration of contact with the floor is 0.01 sec. Then average acceleration during contact is:

A ball falls on the surface from 10 m height and rebounds to 2.5 m. If

1.	A ball falls on the surface from 10 m height and rebounds to 2.5 m. If the duration of contact with the floor is 0.01 sec. Then average acceleration during contact is:
Answer» 2100 `MS^(-2)` 1400 `ms^(-2)` 700 `ms^(-2)` 400 `ms^(-2)` Solution :Here `a=(V_2-V_1)/(t)` Now `v_2=SQRT(2gh_2)=sqrt(2xx10xx2.5)=sqrt(50)` and `v_1=sqrt(2xx10xx10)=sqrt(200)` `:. (sqrt(200)-sqrt(50))/(0.01)=a` or a=2100 `ms^(-2)`

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A ball falls on the surface from 10 m height and rebounds to 2.5 m. If the duration of contact with the floor is 0.01 sec. Then average acceleration during contact is:

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