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A ball floats on the surface of water in a container exposed to the atmosphere. Volume `V_(1)` of its volume is inside the water. The container is now covered and the air is pumped out. Now let `V_(2)` be the volume immersed in water. ThenA. `V_(1) = V_(2)`B. `V_(1) gt V_(2)`C. `V_(2) gt V_(1)`D. `V_(2) = 0`

Answer» Correct Answer - C


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