1.

A ball is allowed to fall from a height of 10 m. There is 40% loss of energy every time it hits the ground. After second impact with the ground, the ball will rise upto

Answer»

10 m
6 m
3.6 m
2.4 m

Solution :Here let `h_1` and `h_2` be the HEIGHTS to which the BALL RISE.
Then`h_1 PROP P.E`
`:.H_1=(60)/(100)xx10=6m`
Similarly `h_2=(60)/(100)xx6=3.6 m`


Discussion

No Comment Found

Related InterviewSolutions