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A ball is dropped from top of the building 100m high. Simultaneously another ball is thrown upwards from bottom of tower with such a velocity that the balls collide midway. What is the speed of 2nd ball ? |
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Answer» 31.6 m/s `t=sqrt((2xx50)/(10))` `t=sqrt(10s)=3.16s` Now durings this time 2 ball should cover disatnce 50 m `:. 50 =uxx3.16-(1)/(2)xx10xx10impliesu=(100)/(3.16)=31.6ms^(-1)` |
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