A ball is dropped on the floor from a height of 10m. It rebounds to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, What is the average acceleration during contact.

A ball is dropped on the floor from a height of 10m. It rebounds to a

1.	A ball is dropped on the floor from a height of 10m. It rebounds to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, What is the average acceleration during contact.
Answer» SOLUTION :`v_1=sqrt2gh=sqrt(2xx10xx10)=sqrt200` `v_2=-sqrt(2xx10xx2.5) =-sqrt50` ACCELERATION `(DELTAV)/(DELTAT) = (v_1-v_2)/(Deltat)=(sqrt200+sqrt50)/0.01 = 2100 m/s^2`

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A ball is dropped on the floor from a height of 10m. It rebounds to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, What is the average acceleration during contact.

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