A ball is projected from a certain point on the surface of a planet at a certain angle with the horizontal surface. The horizontal and vertical displacements x and y vary with time t in second as x=10sqrt(3)t and y=10t-t^(2)The maximum height attained by the ball is:

A ball is projected from a certain point on the surface of a planet at

1.	A ball is projected from a certain point on the surface of a planet at a certain angle with the horizontal surface. The horizontal and vertical displacements x and y vary with time t in second as x=10sqrt(3)t and y=10t-t^(2)The maximum height attained by the ball is:
Answer» 100m 75m 50m 25m Solution :Here `v_(y)=d/(dt)(y)=d/(dt)(10t-t^(2))=10-2t` At the highest POINT `v_(y)=0:.10-2t=0` or `t=5s` Putting above `h_(max)=10xx5-25=25m`

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A ball is projected from a certain point on the surface of a planet at a certain angle with the horizontal surface. The horizontal and vertical displacements x and y vary with time t in second as x=10sqrt(3)t and y=10t-t^(2)The maximum height attained by the ball is:

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