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A ball Is projected horizontally from the top of a tower with velocity 4m/s. The velocity of the ball after 0.7s (g = 10m/s^2 ) is |
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Answer» 11m/s t = `sqrt(v^2x +v^2y) =sqrt(4^2+ g t^2)= sqrt(16+(10xx7)^2)` = 8m/s. |
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