1.

A ball is projected upwards from the top of a tower with velocity 50 ms^(-1) making an angle of 30° with the horizontal. If the height of the tower is 70 m, after what time from the instant of throwing, will the ball reach the ground (g = 10 ms^(-2) ):

Answer»

2s
5s
7s
9s

Solution :Here -`u_(y)=usintheta=50xx1/2=25ms^(-1)`
`:.h=-70m,a=-10m//s^(2)`
USING `h=ut + 1/2g t^(2)`
`-70=25t - 5t^(2)`
SOLVING this, we GET t=7s


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