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A ball is projected vertically up with a speed of 50 m/s. Find the maximum height, the time to reach the maximum height, and the speed at of the maximum height. (g = 10 m/ s2) |
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Answer» Initial speed u = 50 m/s ; g = 10 m/s2 Maximum height reaches by the body (h) = \(\frac{u^2}{2g}=\frac{50\,\times\,50}{2\,\times\,10}\) = 125 m Time taken to reach the maximum height (t) = \(\frac{u}{g}=\frac{50}{10}\) = 5 sec. After reaching maximum height, the velocity becomes ‘zero’. |
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