A ball is released from the top of a tower of height h meters. It take

1.	A ball is released from the top of a tower of height h meters. It takes T second to reach the ground. What is the position of the ball in T/3 second -
Answer» "" ❤️ Answer ❤️"" the acceleration of the ball will be g. Initial velocity will be 0. in T sec. BODY travels H mts. by applying equations of motion we get s= ut+ (1/2)gT 2 h= (1/2)gT 2 ------[1] in T/3 sec h 1 (1/2)gT 2 = (1/2)g( 3 T ) 2 (1/2)g( 9 T2 ) -------[2] from [1]and[2]we get h 1 9 h distance from point of release. therefore distance from ground is h− 9 h = 9 8h ☺️ Always KEEP smiling ☺️✌️

A ball is released from the top of a tower of height h meters. It takes T second to reach the ground. What is the position of the ball in T/3 second -

Answer»

the acceleration of the ball will be g. Initial velocity will be 0.

in T sec. BODY travels H mts.

by applying equations of motion we get

s= ut+ (1/2)gT

h= (1/2)gT

------[1]

in T/3 sec

(1/2)gT

(1/2)g(

) 2

(1/2)g(

)

-------[2]

from

[1]and[2]we get

distance from point of release.

therefore distance from ground is

h−