1.

A ball is released from the top of a tower of heighth metre. It takes T second to each the ground. What is the position of the ball at T/3second ?

Answer»

`h/9` meter from the GROUND
`(7h)/(9)` meter from the ground
`(8h)/(9)` meter from the ground
`(17h)/(18)` meter from the ground

Solution :Here time to REACH the ground is given byh=1/2 `G t^(2)=1//2g t^(2)`
In T/3 s the DISATNCE fallen is `=(1)/(2)gxx(T^(2))/(9)=(h)/(9)`
`:.`DISTANCE from the ground `=h -(h)/(9)=(8h)/(9)`


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