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A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in T//3sccond? |
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Answer» h/9 metre from the GROUND `:. h=0+(1)/(2)gT^(2) or 2H=gT^(2)` After `T//3s, s=0+(1)/(2)xxg((T)/(3))^(2)=(gT^(2))/(18)` or `18 s - gT^(2)` From (i) and (ii) 18 s =2h or m from top. `:.` Height from ground `- h - (h)/(9)=(8h)/(9)` m . |
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