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A ball is thrown from the top of a tower of 67 m high with a velocity 24.4 ms^(-1) at an clevation of 30^(@) above the horizontal. What is the distance from the foot of the tower to the point where the ball hits the ground? |
Answer» Solution : `h=(1)/(2) "GT"^(2)-(-U sin THETA) t "" rArr t=5` sec ONDS ALSO, `d=(u cos theta t=105.65m)` |
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