A ball is thrown upwards from the ground. It is at a height 100 m in upward and downward journeys at time t_1 andt_2 respectively. If g = 10 m/s^(2), then the product of t_1 . t_2 is:

A ball is thrown upwards from the ground. It is at a height 100 m in u

1.	A ball is thrown upwards from the ground. It is at a height 100 m in upward and downward journeys at time t_1 andt_2 respectively. If g = 10 m/s^(2), then the product of t_1 . t_2 is:
Answer» 10 20 40 50 Solution :Here 100 =`ut-(1)/(2)G t^2=ut-5t^2` or `5t^2 -ut+100=0` There are two roots for this equation .Let `t_1` and `t_2` be the value. The PRODUCT of the roots `t_1.t_2=(100)/(5)=20`

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A ball is thrown upwards from the ground. It is at a height 100 m in upward and downward journeys at time t_1 andt_2 respectively. If g = 10 m/s^(2), then the product of t_1 . t_2 is:

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