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A ball is thrown vertically upward with a velocity of 49 m/s. Calculate, i) the maximum height to which it rises. ii) the total time to return to the surface of the earth. |
Answer» i) u = 49 m/s, g = 9.8 m/s2. Maximum height = u2 /2g = (49 x 49)/(2 x 9.8) = 122.5 m. ii) Total time to return to the surface of the earth = 2u/g = (2 x 49 )/9.8 = 10 s. |
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