InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A ball moving with a velocity ef 10 impinges on a vertical wall at an angle of 45° with the normal to the wall. After the collision, the ball moves on the other side of the normal at an angle of 45° with the normal. The coefficient of restitution is 0.5. The velocity of the ball after the collision will be |
|
Answer» 2 `ms^(-1)` `e=("Normal component of R.V after collison")/("Normal component of R.V before collison")` `e=0.5=(v COS 45^(@))/(10 cos 45^(@))=(v)/(10)` or `v=10xx0.5=5 ms^(-1)` |
|