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A ball of 200 g is at one end of a string of length 20 cm. It is revolved in a horizontal circle at an angular frequency of 6 rpm. Find (i) the angular velocity, (ii) the linear velocity, (iii) the centripetal acceleration, (iv) the centripetal force and (v) the tension in the string. |
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Answer» SOLUTION :(i) The ANGULAR velocity `omega =(2piN)/t =(2pi xx 6)/60 = pi/5 = 0.6284 "RAD" s^(-1)` (ii) The linear velocity, `v= romega` `=0.20 xx 0.6284 = 0.1257 MS^(-1)` (iii) The centripetal acceleration `a_( c)=r omega^(2)` `=0.20 xx (0.6284)^(2) = 0.0790 ms^(-2)` |
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