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A ball of 200g is at one end of a stringof length 20 cm. it is revolved in a horizontal circle at an angular frequency of 6 rpm. Find (i) the angular velocity (ii) the linear velocity, (iii) the centripetal acceleration. |
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Answer» SOLUTION :(i) The angular velocity, ` omega=(2piN)/(t)=(2pi XX 6)/(60)=(pi)/(5)=0.6284 rad s^(-1)` (ii) the linear velocity `V= r omega` `=0.20xx0.6284=0.1257 m s^(-1)` (iii) The CENTRIPETAL ACCELERATION `a_(c)=r omega^(2)` `=0.20 xx (0.6284)^(2)=0.0970 m s^(-2)` |
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