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A ball of mass 100 g is moving with a velocity of 10 ms^(-1). On being hit with bat rebounds with a velocity of 10 ms^(-1). The force of the ball by the bat acts for 0.01 s, then the force exerted on the ball by the bat is

Answer»

50 N
100 N
200 N
400 N

Solution :`V_(1) = 10 ms^(-1), v_(2) = - 10 ms^(-1), DELTA t = 0.01 s,m= 100 G`
FORCE`=(m(v_(1)-v_(2)))/(Delta t)`
`=(0.1[10+10])/0.01 = 200 N`


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