InterviewSolution
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InterviewSolution
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A ball of mass (m) is thrown vertically up. Another ball of mass ` 2 m` is thrown at an angle ` theta` with the vertical. Both of them stay in air for the same period of time. What is the ratio of the height attained by two balls. |
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Answer» For the ball thrown vertically upwards, the time taken by the ball to come back is `T_(1)=(2u_(1))/(g)` For the ball projected at an angle `theta` with their vertical, the time of flight is `T_(2)=2u_(2) cos theta/g` Since time of flights for the balls is same, so `(2u_(1))/(g)=(2u_(2)cos theta)/(g)` or `u_(1)=u_(2) cos theta` `because h_(1)=(u_(1)^(2))/(2g)` and `h_(2)=(u_(2)^(2))/(2g) cos ^(2) theta therefore (h_(1))/(h_(2))=(u_(1)^(2))/(u_(2)^(2)cos^(2)theta)=(u_(2)^(2)cos^(2)theta)/(u_(2)^(2)cos^(2)theta)=1` |
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